Let
be three cevians concurrent at an interior point
of a triangle
. Prove that if two of the quadrangles
are circumscribable, so is the third.
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Let $AX,BY,CZ$ be three cevians concurrent at an interior point $D$ of a triangle $ABC$. Prove that if two of the quadrangles $DY AZ,DZBX,DXCY$ are circumscribable, so is the third.
Školjka