In the triangle
with
a parallel
to
is drawn through the incenter
of the triangle, where
lies on the side
The point
on the side
is such that
Show that
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In the triangle $ABC,$ with $\angle A = 60 ^{\circ},$ a parallel $IF$ to $AC$ is drawn through the incenter $I$ of the triangle, where $F$ lies on the side $AB.$ The point $P$ on the side $BC$ is such that $3BP = BC.$ Show that $\angle BFP = \frac{\angle B}{2}.$
Školjka